How to fetch data with in a variable [duplicate] - php

From PHP code I want to create an json array:
[
{"region":"valore","price":"valore2"},
{"region":"valore","price":"valore2"},
{"region":"valore","price":"valore2"}
]
How can I do this?

Easy peasy lemon squeezy: http://www.php.net/manual/en/function.json-encode.php
<?php
$arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
echo json_encode($arr);
?>
There's a post by andyrusterholz at g-m-a-i-l dot c-o-m on the aforementioned page that can also handle complex nested arrays (if that's your thing).

Use PHP's native json_encode, like this:
<?php
$arr = array(
array(
"region" => "valore",
"price" => "valore2"
),
array(
"region" => "valore",
"price" => "valore2"
),
array(
"region" => "valore",
"price" => "valore2"
)
);
echo json_encode($arr);
?>
Update: To answer your question in the comment. You do it like this:
$named_array = array(
"nome_array" => array(
array(
"foo" => "bar"
),
array(
"foo" => "baz"
)
)
);
echo json_encode($named_array);

Simple: Just create a (nested) PHP array and call json_encode on it. Numeric arrays translate into JSON lists ([]), associative arrays and PHP objects translate into objects ({}). Example:
$a = array(
array('foo' => 'bar'),
array('foo' => 'baz'));
$json = json_encode($a);
Gives you:
[{"foo":"bar"},{"foo":"baz"}]

Best way that you should go every time for creating json in php is to first convert values in ASSOCIATIVE array.
After that just simply encode using json_encode($associativeArray). I think it is the best way to create json in php because whenever we are fetching result form sql query in php most of the time we got values using fetch_assoc function, which also return one associative array.
$associativeArray = array();
$associativeArray ['FirstValue'] = 'FirstValue';
...
etc.
After that.
json_encode($associativeArray);

also for array you can use short annotattion:
$arr = [
[
"region" => "valore",
"price" => "valore2"
],
[
"region" => "valore",
"price" => "valore2"
],
[
"region" => "valore",
"price" => "valore2"
]
];
echo json_encode($arr);

Just typing this single line would give you a json array ,
echo json_encode($array);
Normally you use json_encode to read data from an ios or android app. so make sure you do not echo anything else other than the accurate json array.

$json_data = '{ "Languages:" : [ "English", "Spanish" ] }';
$lang_data = json_decode($json_data);
var_dump($lang_data);

That's how I am able to do with the help of solution given by #tdammers below.
The following line will be placed inside foreach loop.
$array[] = array('power' => trim("Some value"), 'time' => "time here" );
And then encode the array with json encode function
json_encode(array('newvalue'=> $array), 200)

<?php
$username=urldecode($_POST['log_user']);
$user="select * from tbl_registration where member_id= '".$username."' ";
$rsuser = $obj->select($user);
if(count($rsuser)>0)
{
// (Status if 2 then its expire) (1= use) ( 0 = not use)
$cheknew="select name,ldate,offer_photo from tbl_offer where status=1 ";
$rscheknew = $obj->selectjson($cheknew);
if(count($rscheknew)>0)
{
$nik=json_encode($rscheknew);
echo "{\"status\" : \"200\" ,\"responce\" : \"201\", \"message\" : \"Get Record\",\"feed\":".str_replace("<p>","",$nik). "}";
}
else
{
$row2="No Record Found";
$nik1=json_encode($row2);
echo "{\"status\" : \"202\", \"responce\" : \"604\",\"message\" : \"No Record Found \",\"feed\":".str_replace("<p>","",$nik1). "}";
}
}
else
{
$row2="Invlid User";
$nik1=json_encode($row2);
echo "{\"status\" : \"404\", \"responce\" : \"602\",\"message\" : \"Invlid User \",\"feed\":".str_replace("<p>","",$nik1). "}";
}
?>

Related

how to push object into a array in php [duplicate]

I am trying to create an JSON object out of a PHP array. The array looks like this:
$post_data = array('item_type_id' => $item_type,
'string_key' => $string_key,
'string_value' => $string_value,
'string_extra' => $string_extra,
'is_public' => $public,
'is_public_for_contacts' => $public_contacts);
The code to encode the JSON look like this:
$post_data = json_encode($post_data);
The JSON file is supposed to look like this in the end:
{
"item": {
"is_public_for_contacts": false,
"string_extra": "100000583627394",
"string_value": "value",
"string_key": "key",
"is_public": true,
"item_type_id": 4,
"numeric_extra": 0
}
}
How can I encapsulate the created JSON code in the "item": { JSON CODE HERE }.
Usually, you would do something like this:
$post_data = json_encode(array('item' => $post_data));
But, as it seems you want the output to be with "{}", you better make sure to force json_encode() to encode as object, by passing the JSON_FORCE_OBJECT constant.
$post_data = json_encode(array('item' => $post_data), JSON_FORCE_OBJECT);
"{}" brackets specify an object and "[]" are used for arrays according to JSON specification.
Although the other answers posted here work, I find the following approach more natural:
$obj = (object) [
'aString' => 'some string',
'anArray' => [ 1, 2, 3 ]
];
echo json_encode($obj);
You just need another layer in your php array:
$post_data = array(
'item' => array(
'item_type_id' => $item_type,
'string_key' => $string_key,
'string_value' => $string_value,
'string_extra' => $string_extra,
'is_public' => $public,
'is_public_for_contacts' => $public_contacts
)
);
echo json_encode($post_data);

Generate php array definition from JSON

My question is a bit different to most like this, I basically want to do the opposite to this question from Haluk.
So I have a JSON string:
{
"main":
{
"title": "QuickPub",
"defaultRole": "BU"
},
"roles":
{
"TU":
{
"name": "testUser",
"code": "TU"
}
}
}
and I want to be able to generate a string containing a php array definition from it:
<?php
return [
"main" =>
[
"title" => "QuickPub",
"defaultRole" => "BU"
],
"roles" =>
[
"TU" =>
[
"name" => "testUser",
"code" => "TU"
]
]
];
?>
EDIT:
I have tried json_decode() but this produces a variable, I need a string that I can put in a php file that will reproduce this without using php_decode.
I think this will solve your problem. First of all convert your json string to an array using json_decode($string,1); then convert that array to string representation using print_r($array,1); this will return your result as array string representation.
For example:
$json='{}' // its a demo
$array= json_decode($json,1); // an array
$result = print_r($array,1);
echo $result;
This is an adaptation of Being Sunny's answer, but using the var_export() function rather than print_r.
As described here by phihad
var_export prints valid php code. Useful if you calculated some values and want the results as a constant in another script
the script:
$json = '{"main":{"title": "QuickPub","defaultRole": "BU"},"roles":{"TU":{"name": "testUser","code": "TU"}}}';
$array = json_decode($json, 1);
$result = var_export($array, 1);
echo $result;
produces:
array(
'main' => array(
'title' => 'QuickPub',
'defaultRole' => 'BU',
),
'roles' => array(
'TU' => array(
'name' => 'testUser',
'code' => 'TU',
),
),
)
This can be achieved using this code:
$output = 'return ' . rtrim(preg_replace(['/{/', '/}/', '/:/'], ['[', ']', ' =>'], $json)) . ';';
this replaces { with [, } with ], and : with =>, trims any whitespace from the end, appends a ; and prepends a return statement.
this produces the output requested in the question bar the open and closing php tags.

PHP & JSON: Inserting an array in a nested array

I am creating a JSON structure to be passed back to Ajax. I would like to insert 'para' => "Hello" into "content" like this:
{
"sections": {
"content": [{
"para": "Hello"
}]
}
}
I tried using this code:
$array = array('sections' => array());
array_push($array["sections"], array("content" => array())); // content must be initialized as empty
array_push($array["sections"][0], array("para" => "Hello"));
But I received this instead:
{
"sections": [{
"content": [],
"0": {
"para": "Hello"
}
}]
}
If I try array_push($array["sections"]["content"], array("para" => "Hello")), I get an error instead. How do I insert an array into "content"? What am I doing wrong?
If I understood your intentions correctly, here's the array structure you're aiming for:
array("sections" => array(
"content" => array("para" => "Hello"),
));
However, in Javascript [] represents an array and {} represents an object. If you're trying to create an object with a property of "0", that's not possible in PHP. Variable names have to start with a letter or underscore.
Here's an array of content objects:
$content = new stdClass();
$content->para = 'hello';
array("sections" => array(
"content" => array($content),
));
To add arrays of contents:
array("sections" => array(
"content" => array(
array("para" => "Hello"),
array("para" => "Hello"),
array("para" => "Hello"),
),
));
You can also construct your own contents array first if you're iterating over an index and then json_encode it. Basic example:
$content = array();
for (i=0; i <3; i++) {
$content[] = array('para' => 'hello');
}
json_encode(array("sections" => array(
"content" => array($content),
)));
To convert that to JSON, put your array inside a json_encode() call.
$array['sections'] = array("content" => array(array("para" => "Hello")));
echo json_encode($array);
will give the result in desired format

How to create an array for JSON using PHP?

From PHP code I want to create an json array:
[
{"region":"valore","price":"valore2"},
{"region":"valore","price":"valore2"},
{"region":"valore","price":"valore2"}
]
How can I do this?
Easy peasy lemon squeezy: http://www.php.net/manual/en/function.json-encode.php
<?php
$arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
echo json_encode($arr);
?>
There's a post by andyrusterholz at g-m-a-i-l dot c-o-m on the aforementioned page that can also handle complex nested arrays (if that's your thing).
Use PHP's native json_encode, like this:
<?php
$arr = array(
array(
"region" => "valore",
"price" => "valore2"
),
array(
"region" => "valore",
"price" => "valore2"
),
array(
"region" => "valore",
"price" => "valore2"
)
);
echo json_encode($arr);
?>
Update: To answer your question in the comment. You do it like this:
$named_array = array(
"nome_array" => array(
array(
"foo" => "bar"
),
array(
"foo" => "baz"
)
)
);
echo json_encode($named_array);
Simple: Just create a (nested) PHP array and call json_encode on it. Numeric arrays translate into JSON lists ([]), associative arrays and PHP objects translate into objects ({}). Example:
$a = array(
array('foo' => 'bar'),
array('foo' => 'baz'));
$json = json_encode($a);
Gives you:
[{"foo":"bar"},{"foo":"baz"}]
Best way that you should go every time for creating json in php is to first convert values in ASSOCIATIVE array.
After that just simply encode using json_encode($associativeArray). I think it is the best way to create json in php because whenever we are fetching result form sql query in php most of the time we got values using fetch_assoc function, which also return one associative array.
$associativeArray = array();
$associativeArray ['FirstValue'] = 'FirstValue';
...
etc.
After that.
json_encode($associativeArray);
also for array you can use short annotattion:
$arr = [
[
"region" => "valore",
"price" => "valore2"
],
[
"region" => "valore",
"price" => "valore2"
],
[
"region" => "valore",
"price" => "valore2"
]
];
echo json_encode($arr);
Just typing this single line would give you a json array ,
echo json_encode($array);
Normally you use json_encode to read data from an ios or android app. so make sure you do not echo anything else other than the accurate json array.
$json_data = '{ "Languages:" : [ "English", "Spanish" ] }';
$lang_data = json_decode($json_data);
var_dump($lang_data);
That's how I am able to do with the help of solution given by #tdammers below.
The following line will be placed inside foreach loop.
$array[] = array('power' => trim("Some value"), 'time' => "time here" );
And then encode the array with json encode function
json_encode(array('newvalue'=> $array), 200)
<?php
$username=urldecode($_POST['log_user']);
$user="select * from tbl_registration where member_id= '".$username."' ";
$rsuser = $obj->select($user);
if(count($rsuser)>0)
{
// (Status if 2 then its expire) (1= use) ( 0 = not use)
$cheknew="select name,ldate,offer_photo from tbl_offer where status=1 ";
$rscheknew = $obj->selectjson($cheknew);
if(count($rscheknew)>0)
{
$nik=json_encode($rscheknew);
echo "{\"status\" : \"200\" ,\"responce\" : \"201\", \"message\" : \"Get Record\",\"feed\":".str_replace("<p>","",$nik). "}";
}
else
{
$row2="No Record Found";
$nik1=json_encode($row2);
echo "{\"status\" : \"202\", \"responce\" : \"604\",\"message\" : \"No Record Found \",\"feed\":".str_replace("<p>","",$nik1). "}";
}
}
else
{
$row2="Invlid User";
$nik1=json_encode($row2);
echo "{\"status\" : \"404\", \"responce\" : \"602\",\"message\" : \"Invlid User \",\"feed\":".str_replace("<p>","",$nik1). "}";
}
?>

Create JSON-object the correct way

I am trying to create an JSON object out of a PHP array. The array looks like this:
$post_data = array('item_type_id' => $item_type,
'string_key' => $string_key,
'string_value' => $string_value,
'string_extra' => $string_extra,
'is_public' => $public,
'is_public_for_contacts' => $public_contacts);
The code to encode the JSON look like this:
$post_data = json_encode($post_data);
The JSON file is supposed to look like this in the end:
{
"item": {
"is_public_for_contacts": false,
"string_extra": "100000583627394",
"string_value": "value",
"string_key": "key",
"is_public": true,
"item_type_id": 4,
"numeric_extra": 0
}
}
How can I encapsulate the created JSON code in the "item": { JSON CODE HERE }.
Usually, you would do something like this:
$post_data = json_encode(array('item' => $post_data));
But, as it seems you want the output to be with "{}", you better make sure to force json_encode() to encode as object, by passing the JSON_FORCE_OBJECT constant.
$post_data = json_encode(array('item' => $post_data), JSON_FORCE_OBJECT);
"{}" brackets specify an object and "[]" are used for arrays according to JSON specification.
Although the other answers posted here work, I find the following approach more natural:
$obj = (object) [
'aString' => 'some string',
'anArray' => [ 1, 2, 3 ]
];
echo json_encode($obj);
You just need another layer in your php array:
$post_data = array(
'item' => array(
'item_type_id' => $item_type,
'string_key' => $string_key,
'string_value' => $string_value,
'string_extra' => $string_extra,
'is_public' => $public,
'is_public_for_contacts' => $public_contacts
)
);
echo json_encode($post_data);

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